- Difficulty: Medium
- Tags: LeetCode, Medium, Tree, Depth-First Search, Binary Tree, leetcode-156, Recursion, O(n), O(1), 🔒
Problem
Given the root
of a binary tree, turn the tree upside down and return the new root.
You can turn a binary tree upside down with the following steps:
- The original left child becomes the new root.
- The original root becomes the new right child.
- The original right child becomes the new left child.
The mentioned steps are done level by level. It is guaranteed that every right node has a sibling (a left node with the same parent) and has no children.
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Example 1:
Input: root = [1,2,3,4,5] Output: [4,5,2,null,null,3,1]
Example 2:
Input: root = [] Output: []
Example 3:
Input: root = [1] Output: [1]
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Constraints:
- The number of nodes in the tree will be in the range
[0, 10]
. 1 <= Node.val <= 10
- Every right node in the tree has a sibling (a left node that shares the same parent).
- Every right node in the tree has no children.