- Difficulty: Hard
- Tags: LeetCode, Hard, Breadth-First Search, Array, Hash Table, leetcode-815, O(|E| + |V|)
Problem
You are given an array routes
representing bus routes where routes[i]
is a bus route that the ith
bus repeats forever.
- For example, if
routes[0] = [1, 5, 7]
, this means that the0th
bus travels in the sequence1 -> 5 -> 7 -> 1 -> 5 -> 7 -> 1 -> ...
forever.
You will start at the bus stop source
(You are not on any bus initially), and you want to go to the bus stop target
. You can travel between bus stops by buses only.
Return the least number of buses you must take to travel from source
to target
. Return -1
if it is not possible.
Example 1:
Input: routes = [[1,2,7],[3,6,7]], source = 1, target = 6 Output: 2 Explanation: The best strategy is take the first bus to the bus stop 7, then take the second bus to the bus stop 6.
Example 2:
Input: routes = [[7,12],[4,5,15],[6],[15,19],[9,12,13]], source = 15, target = 12 Output: -1
Constraints:
1 <= routes.length <= 500
.1 <= routes[i].length <= 105
- All the values of
routes[i]
are unique. sum(routes[i].length) <= 105
0 <= routes[i][j] < 106
0 <= source, target < 106