- Difficulty: Medium
- Tags: LeetCode, Medium, Bit Manipulation, Array, Hash Table, String, Prefix Sum, leetcode-1177, O(m + n), O(n)
Problem
You are given a string s
and array queries
where queries[i] = [lefti, righti, ki]
. We may rearrange the substring s[lefti...righti]
for each query and then choose up to ki
of them to replace with any lowercase English letter.
If the substring is possible to be a palindrome string after the operations above, the result of the query is true
. Otherwise, the result is false
.
Return a boolean array answer
where answer[i]
is the result of the ith
query queries[i]
.
Note that each letter is counted individually for replacement, so if, for example s[lefti...righti] = "aaa"
, and ki = 2
, we can only replace two of the letters. Also, note that no query modifies the initial string s
.
Example :
Input: s = "abcda", queries = [[3,3,0],[1,2,0],[0,3,1],[0,3,2],[0,4,1]] Output: [true,false,false,true,true] Explanation: queries[0]: substring = "d", is palidrome. queries[1]: substring = "bc", is not palidrome. queries[2]: substring = "abcd", is not palidrome after replacing only 1 character. queries[3]: substring = "abcd", could be changed to "abba" which is palidrome. Also this can be changed to "baab" first rearrange it "bacd" then replace "cd" with "ab". queries[4]: substring = "abcda", could be changed to "abcba" which is palidrome.
Example 2:
Input: s = "lyb", queries = [[0,1,0],[2,2,1]] Output: [false,true]
Constraints:
1 <= s.length, queries.length <= 105
0 <= lefti <= righti < s.length
0 <= ki <= s.length
s
consists of lowercase English letters.