- Difficulty: Medium
- Tags: LeetCode, Medium, Greedy, Bit Manipulation, Array, Hash Table, leetcode-1386, O(n)
Problem
A cinema has n
rows of seats, numbered from 1 to n
and there are ten seats in each row, labelled from 1 to 10 as shown in the figure above.
Given the array reservedSeats
containing the numbers of seats already reserved, for example, reservedSeats[i] = [3,8]
means the seat located in row 3 and labelled with 8 is already reserved.
Return the maximum number of four-person groups you can assign on the cinema seats. A four-person group occupies four adjacent seats in one single row. Seats across an aisle (such as [3,3] and [3,4]) are not considered to be adjacent, but there is an exceptional case on which an aisle split a four-person group, in that case, the aisle split a four-person group in the middle, which means to have two people on each side.
Example 1:
Input: n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]] Output: 4 Explanation: The figure above shows the optimal allocation for four groups, where seats mark with blue are already reserved and contiguous seats mark with orange are for one group.
Example 2:
Input: n = 2, reservedSeats = [[2,1],[1,8],[2,6]] Output: 2
Example 3:
Input: n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]] Output: 4
Constraints:
1 <= n <= 10^9
1 <= reservedSeats.length <= min(10*n, 10^4)
reservedSeats[i].length == 2
1 <= reservedSeats[i][0] <= n
1 <= reservedSeats[i][1] <= 10
- All
reservedSeats[i]
are distinct.