- Difficulty: Hard
- Tags: LeetCode, Hard, Bit Manipulation, Array, Two Pointers, Dynamic Programming, Bitmask, leetcode-1755, O(n * 2^(n/2)), O(2^(n/2)), Meet in the Middle
Problem
You are given an integer array nums
and an integer goal
.
You want to choose a subsequence of nums
such that the sum of its elements is the closest possible to goal
. That is, if the sum of the subsequence's elements is sum
, then you want to minimize the absolute difference abs(sum - goal)
.
Return the minimum possible value of abs(sum - goal)
.
Note that a subsequence of an array is an array formed by removing some elements (possibly all or none) of the original array.
Example 1:
Input: nums = [5,-7,3,5], goal = 6 Output: 0 Explanation: Choose the whole array as a subsequence, with a sum of 6. This is equal to the goal, so the absolute difference is 0.
Example 2:
Input: nums = [7,-9,15,-2], goal = -5 Output: 1 Explanation: Choose the subsequence [7,-9,-2], with a sum of -4. The absolute difference is abs(-4 - (-5)) = abs(1) = 1, which is the minimum.
Example 3:
Input: nums = [1,2,3], goal = -7 Output: 7
Constraints:
1 <= nums.length <= 40
-107 <= nums[i] <= 107
-109 <= goal <= 109