- Difficulty: Hard
- Tags: LeetCode, Hard, Array, Bucket Sort, Ordered Set, Sorting, Sliding Window, leetcode-220, Binary Search Tree, O(nlogk), O(k), Medium
Problem
You are given an integer array nums and two integers indexDiff and valueDiff.
Find a pair of indices (i, j) such that:
i != j,abs(i - j) <= indexDiff.abs(nums[i] - nums[j]) <= valueDiff, and
Return true if such pair exists or false otherwise.
Example 1:
Input: nums = [1,2,3,1], indexDiff = 3, valueDiff = 0 Output: true Explanation: We can choose (i, j) = (0, 3). We satisfy the three conditions: i != j --> 0 != 3 abs(i - j) <= indexDiff --> abs(0 - 3) <= 3 abs(nums[i] - nums[j]) <= valueDiff --> abs(1 - 1) <= 0
Example 2:
Input: nums = [1,5,9,1,5,9], indexDiff = 2, valueDiff = 3 Output: false Explanation: After trying all the possible pairs (i, j), we cannot satisfy the three conditions, so we return false.
Constraints:
2 <= nums.length <= 105-109 <= nums[i] <= 1091 <= indexDiff <= nums.length0 <= valueDiff <= 109