- Difficulty: Medium
- Tags: LeetCode, Medium, Design, Hash Table, Ordered Set, Heap (Priority Queue), leetcode-2349, O(n), Sorted List, BST
Problem
Design a number container system that can do the following:
- Insert or Replace a number at the given index in the system.
- Return the smallest index for the given number in the system.
Implement the NumberContainers
class:
NumberContainers()
Initializes the number container system.void change(int index, int number)
Fills the container atindex
with thenumber
. If there is already a number at thatindex
, replace it.int find(int number)
Returns the smallest index for the givennumber
, or-1
if there is no index that is filled bynumber
in the system.
Example 1:
Input ["NumberContainers", "find", "change", "change", "change", "change", "find", "change", "find"] [[], [10], [2, 10], [1, 10], [3, 10], [5, 10], [10], [1, 20], [10]] Output [null, -1, null, null, null, null, 1, null, 2] Explanation NumberContainers nc = new NumberContainers(); nc.find(10); // There is no index that is filled with number 10. Therefore, we return -1. nc.change(2, 10); // Your container at index 2 will be filled with number 10. nc.change(1, 10); // Your container at index 1 will be filled with number 10. nc.change(3, 10); // Your container at index 3 will be filled with number 10. nc.change(5, 10); // Your container at index 5 will be filled with number 10. nc.find(10); // Number 10 is at the indices 1, 2, 3, and 5. Since the smallest index that is filled with 10 is 1, we return 1. nc.change(1, 20); // Your container at index 1 will be filled with number 20. Note that index 1 was filled with 10 and then replaced with 20. nc.find(10); // Number 10 is at the indices 2, 3, and 5. The smallest index that is filled with 10 is 2. Therefore, we return 2.
Constraints:
1 <= index, number <= 109
- At most
105
calls will be made in total tochange
andfind
.