- Difficulty: Easy
- Tags: LeetCode, Easy, Array, Simulation, leetcode-2660, O(n), O(1), Medium
Problem
You are given two 0-indexed integer arrays player1
and player2
, representing the number of pins that player 1 and player 2 hit in a bowling game, respectively.
The bowling game consists of n
turns, and the number of pins in each turn is exactly 10.
Assume a player hits xi
pins in the ith turn. The value of the ith turn for the player is:
2xi
if the player hits 10 pins in either (i - 1)th or (i - 2)th turn.- Otherwise, it is
xi
.
The score of the player is the sum of the values of their n
turns.
Return
- 1 if the score of player 1 is more than the score of player 2,
- 2 if the score of player 2 is more than the score of player 1, and
- 0 in case of a draw.
Example 1:
Input: player1 = [5,10,3,2], player2 = [6,5,7,3]
Output: 1
Explanation:
The score of player 1 is 5 + 10 + 2*3 + 2*2 = 25.
The score of player 2 is 6 + 5 + 7 + 3 = 21.
Example 2:
Input: player1 = [3,5,7,6], player2 = [8,10,10,2]
Output: 2
Explanation:
The score of player 1 is 3 + 5 + 7 + 6 = 21.
The score of player 2 is 8 + 10 + 2*10 + 2*2 = 42.
Example 3:
Input: player1 = [2,3], player2 = [4,1]
Output: 0
Explanation:
The score of player1 is 2 + 3 = 5.
The score of player2 is 4 + 1 = 5.
Example 4:
Input: player1 = [1,1,1,10,10,10,10], player2 = [10,10,10,10,1,1,1]
Output: 2
Explanation:
The score of player1 is 1 + 1 + 1 + 10 + 2*10 + 2*10 + 2*10 = 73.
The score of player2 is 10 + 2*10 + 2*10 + 2*10 + 2*1 + 2*1 + 1 = 75.
Constraints:
n == player1.length == player2.length
1 <= n <= 1000
0 <= player1[i], player2[i] <= 10