- Difficulty: Medium
- Tags: LeetCode, Medium, Depth-First Search, Breadth-First Search, Array, Dynamic Programming, Matrix, leetcode-2556, O(m * n), O(m + n), DP, DFS
Problem
You are given a 0-indexed m x n
binary matrix grid
. You can move from a cell (row, col)
to any of the cells (row + 1, col)
or (row, col + 1)
that has the value 1
. The matrix is disconnected if there is no path from (0, 0)
to (m - 1, n - 1)
.
You can flip the value of at most one (possibly none) cell. You cannot flip the cells (0, 0)
and (m - 1, n - 1)
.
Return true
if it is possible to make the matrix disconnect or false
otherwise.
Note that flipping a cell changes its value from 0
to 1
or from 1
to 0
.
Example 1:
Input: grid = [[1,1,1],[1,0,0],[1,1,1]] Output: true Explanation: We can change the cell shown in the diagram above. There is no path from (0, 0) to (2, 2) in the resulting grid.
Example 2:
Input: grid = [[1,1,1],[1,0,1],[1,1,1]] Output: false Explanation: It is not possible to change at most one cell such that there is not path from (0, 0) to (2, 2).
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 1000
1 <= m * n <= 105
grid[i][j]
is either0
or1
.grid[0][0] == grid[m - 1][n - 1] == 1