- Difficulty: Easy
- Tags: LeetCode, Easy, Tree, Depth-First Search, Binary Tree, leetcode-2331, O(n), O(h), DFS
Problem
You are given the root
of a full binary tree with the following properties:
- Leaf nodes have either the value
0
or1
, where0
representsFalse
and1
representsTrue
. - Non-leaf nodes have either the value
2
or3
, where2
represents the booleanOR
and3
represents the booleanAND
.
The evaluation of a node is as follows:
- If the node is a leaf node, the evaluation is the value of the node, i.e.
True
orFalse
. - Otherwise, evaluate the node's two children and apply the boolean operation of its value with the children's evaluations.
Return the boolean result of evaluating the root
node.
A full binary tree is a binary tree where each node has either 0
or 2
children.
A leaf node is a node that has zero children.
Example 1:
Input: root = [2,1,3,null,null,0,1] Output: true Explanation: The above diagram illustrates the evaluation process. The AND node evaluates to False AND True = False. The OR node evaluates to True OR False = True. The root node evaluates to True, so we return true.
Example 2:
Input: root = [0] Output: false Explanation: The root node is a leaf node and it evaluates to false, so we return false.
Constraints:
- The number of nodes in the tree is in the range
[1, 1000]
. 0 <= Node.val <= 3
- Every node has either
0
or2
children. - Leaf nodes have a value of
0
or1
. - Non-leaf nodes have a value of
2
or3
.