- Difficulty: Hard
- Tags: LeetCode, Hard, Depth-First Search, Breadth-First Search, Union Find, Graph, Sorting, leetcode-2092, O(nlogn), BFS, DFS
Problem
You are given an integer n
indicating there are n
people numbered from 0
to n - 1
. You are also given a 0-indexed 2D integer array meetings
where meetings[i] = [xi, yi, timei]
indicates that person xi
and person yi
have a meeting at timei
. A person may attend multiple meetings at the same time. Finally, you are given an integer firstPerson
.
Person 0
has a secret and initially shares the secret with a person firstPerson
at time 0
. This secret is then shared every time a meeting takes place with a person that has the secret. More formally, for every meeting, if a person xi
has the secret at timei
, then they will share the secret with person yi
, and vice versa.
The secrets are shared instantaneously. That is, a person may receive the secret and share it with people in other meetings within the same time frame.
Return a list of all the people that have the secret after all the meetings have taken place. You may return the answer in any order.
Example 1:
Input: n = 6, meetings = [[1,2,5],[2,3,8],[1,5,10]], firstPerson = 1 Output: [0,1,2,3,5] Explanation: At time 0, person 0 shares the secret with person 1. At time 5, person 1 shares the secret with person 2. At time 8, person 2 shares the secret with person 3. At time 10, person 1 shares the secret with person 5. Thus, people 0, 1, 2, 3, and 5 know the secret after all the meetings.
Example 2:
Input: n = 4, meetings = [[3,1,3],[1,2,2],[0,3,3]], firstPerson = 3 Output: [0,1,3] Explanation: At time 0, person 0 shares the secret with person 3. At time 2, neither person 1 nor person 2 know the secret. At time 3, person 3 shares the secret with person 0 and person 1. Thus, people 0, 1, and 3 know the secret after all the meetings.
Example 3:
Input: n = 5, meetings = [[3,4,2],[1,2,1],[2,3,1]], firstPerson = 1 Output: [0,1,2,3,4] Explanation: At time 0, person 0 shares the secret with person 1. At time 1, person 1 shares the secret with person 2, and person 2 shares the secret with person 3. Note that person 2 can share the secret at the same time as receiving it. At time 2, person 3 shares the secret with person 4. Thus, people 0, 1, 2, 3, and 4 know the secret after all the meetings.
Constraints:
2 <= n <= 105
1 <= meetings.length <= 105
meetings[i].length == 3
0 <= xi, yi <= n - 1
xi != yi
1 <= timei <= 105
1 <= firstPerson <= n - 1