- Difficulty: Medium
- Tags: LeetCode, Medium, Recursion, String, Simulation, leetcode-1545, O(n), O(1)
Problem
Given two positive integers n
and k
, the binary string Sn
is formed as follows:
S1 = "0"
Si = Si - 1 + "1" + reverse(invert(Si - 1))
fori > 1
Where +
denotes the concatenation operation, reverse(x)
returns the reversed string x
, and invert(x)
inverts all the bits in x
(0
changes to 1
and 1
changes to 0
).
For example, the first four strings in the above sequence are:
S1 = "0"
S2 = "011"
S3 = "0111001"
S4 = "011100110110001"
Return the kth
bit in Sn
. It is guaranteed that k
is valid for the given n
.
Example 1:
Input: n = 3, k = 1 Output: "0" Explanation: S3 is "0111001". The 1st bit is "0".
Example 2:
Input: n = 4, k = 11 Output: "1" Explanation: S4 is "011100110110001". The 11th bit is "1".
Constraints:
1 <= n <= 20
1 <= k <= 2n - 1