- Difficulty: Medium
- Tags: LeetCode, Medium, Array, Hash Table, Binary Search, Counting, Matrix, leetcode-1198, O(m * n), O(n), 🔒
Problem
Given an m x n matrix mat where every row is sorted in strictly increasing order, return the smallest common element in all rows.
If there is no common element, return -1.
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Example 1:
Input: mat = [[1,2,3,4,5],[2,4,5,8,10],[3,5,7,9,11],[1,3,5,7,9]] Output: 5
Example 2:
Input: mat = [[1,2,3],[2,3,4],[2,3,5]] Output: 2
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Constraints:
m == mat.lengthn == mat[i].length1 <= m, n <= 5001 <= mat[i][j] <= 104mat[i]is sorted in strictly increasing order.