- Difficulty: Medium
- Tags: LeetCode, Medium, Bit Manipulation, String, leetcode-751, O(n), O(1)
Problem
An IP address is a formatted 32-bit unsigned integer where each group of 8 bits is printed as a decimal number and the dot character '.'
splits the groups.
- For example, the binary number
00001111 10001000 11111111 01101011
(spaces added for clarity) formatted as an IP address would be"15.136.255.107"
.
A CIDR block is a format used to denote a specific set of IP addresses. It is a string consisting of a base IP address, followed by a slash, followed by a prefix length k
. The addresses it covers are all the IPs whose first k
bits are the same as the base IP address.
- For example,
"123.45.67.89/20"
is a CIDR block with a prefix length of20
. Any IP address whose binary representation matches01111011 00101101 0100xxxx xxxxxxxx
, wherex
can be either0
or1
, is in the set covered by the CIDR block.
You are given a start IP address ip
and the number of IP addresses we need to cover n
. Your goal is to use as few CIDR blocks as possible to cover all the IP addresses in the inclusive range [ip, ip + n - 1]
exactly. No other IP addresses outside of the range should be covered.
Return the shortest list of CIDR blocks that covers the range of IP addresses. If there are multiple answers, return any of them.
Example 1:
Input: ip = "255.0.0.7", n = 10 Output: ["255.0.0.7/32","255.0.0.8/29","255.0.0.16/32"] Explanation: The IP addresses that need to be covered are: - 255.0.0.7 -> 11111111 00000000 00000000 00000111 - 255.0.0.8 -> 11111111 00000000 00000000 00001000 - 255.0.0.9 -> 11111111 00000000 00000000 00001001 - 255.0.0.10 -> 11111111 00000000 00000000 00001010 - 255.0.0.11 -> 11111111 00000000 00000000 00001011 - 255.0.0.12 -> 11111111 00000000 00000000 00001100 - 255.0.0.13 -> 11111111 00000000 00000000 00001101 - 255.0.0.14 -> 11111111 00000000 00000000 00001110 - 255.0.0.15 -> 11111111 00000000 00000000 00001111 - 255.0.0.16 -> 11111111 00000000 00000000 00010000 The CIDR block "255.0.0.7/32" covers the first address. The CIDR block "255.0.0.8/29" covers the middle 8 addresses (binary format of 11111111 00000000 00000000 00001xxx). The CIDR block "255.0.0.16/32" covers the last address. Note that while the CIDR block "255.0.0.0/28" does cover all the addresses, it also includes addresses outside of the range, so we cannot use it.
Example 2:
Input: ip = "117.145.102.62", n = 8 Output: ["117.145.102.62/31","117.145.102.64/30","117.145.102.68/31"]
Constraints:
7 <= ip.length <= 15
ip
is a valid IPv4 on the form"a.b.c.d"
wherea
,b
,c
, andd
are integers in the range[0, 255]
.1 <= n <= 1000
- Every implied address
ip + x
(forx < n
) will be a valid IPv4 address.