- Difficulty: Hard
- Tags: LeetCode, Hard, Breadth-First Search, Array, Hash Table, leetcode-1345, O(n)
Problem
Given an array of integers arr
, you are initially positioned at the first index of the array.
In one step you can jump from index i
to index:
i + 1
where:i + 1 < arr.length
.i - 1
where:i - 1 >= 0
.j
where:arr[i] == arr[j]
andi != j
.
Return the minimum number of steps to reach the last index of the array.
Notice that you can not jump outside of the array at any time.
Example 1:
Input: arr = [100,-23,-23,404,100,23,23,23,3,404] Output: 3 Explanation: You need three jumps from index 0 --> 4 --> 3 --> 9. Note that index 9 is the last index of the array.
Example 2:
Input: arr = [7] Output: 0 Explanation: Start index is the last index. You do not need to jump.
Example 3:
Input: arr = [7,6,9,6,9,6,9,7] Output: 1 Explanation: You can jump directly from index 0 to index 7 which is last index of the array.
Constraints:
1 <= arr.length <= 5 * 104
-108 <= arr[i] <= 108