(LeetCode 2297):

Problem

You are given a 0-indexed integer array nums of length n. You are initially standing at index 0. You can jump from index i to index j where i < j if:

  • nums[i] <= nums[j] and nums[k] < nums[i] for all indexes k in the range i < k < j, or
  • nums[i] > nums[j] and nums[k] >= nums[i] for all indexes k in the range i < k < j.

You are also given an integer array costs of length n where costs[i] denotes the cost of jumping to index i.

Return the minimum cost to jump to the index n - 1.

 

Example 1:

Input: nums = [3,2,4,4,1], costs = [3,7,6,4,2]
Output: 8
Explanation: You start at index 0.
- Jump to index 2 with a cost of costs[2] = 6.
- Jump to index 4 with a cost of costs[4] = 2.
The total cost is 8. It can be proven that 8 is the minimum cost needed.
Two other possible paths are from index 0 -> 1 -> 4 and index 0 -> 2 -> 3 -> 4.
These have a total cost of 9 and 12, respectively.

Example 2:

Input: nums = [0,1,2], costs = [1,1,1]
Output: 2
Explanation: Start at index 0.
- Jump to index 1 with a cost of costs[1] = 1.
- Jump to index 2 with a cost of costs[2] = 1.
The total cost is 2. Note that you cannot jump directly from index 0 to index 2 because nums[0] <= nums[1].

 

Constraints:

  • n == nums.length == costs.length
  • 1 <= n <= 105
  • 0 <= nums[i], costs[i] <= 105