- Difficulty: Medium
- Tags: LeetCode, Medium, Array, Hash Table, Two Pointers, Binary Search, Sorting, leetcode-532, O(n), Easy
Problem
Given an array of integers nums
and an integer k
, return the number of unique k-diff pairs in the array.
A k-diff pair is an integer pair (nums[i], nums[j])
, where the following are true:
0 <= i, j < nums.length
i != j
|nums[i] - nums[j]| == k
Notice that |val|
denotes the absolute value of val
.
Example 1:
Input: nums = [3,1,4,1,5], k = 2 Output: 2 Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). Although we have two 1s in the input, we should only return the number of unique pairs.
Example 2:
Input: nums = [1,2,3,4,5], k = 1 Output: 4 Explanation: There are four 1-diff pairs in the array, (1, 2), (2, 3), (3, 4) and (4, 5).
Example 3:
Input: nums = [1,3,1,5,4], k = 0 Output: 1 Explanation: There is one 0-diff pair in the array, (1, 1).
Constraints:
1 <= nums.length <= 104
-107 <= nums[i] <= 107
0 <= k <= 107