- Difficulty: Easy
- Tags: LeetCode, Easy, Array, Prefix Sum, leetcode-2574, O(n), O(1)
Problem
Given a 0-indexed integer array nums
, find a 0-indexed integer array answer
where:
answer.length == nums.length
.answer[i] = |leftSum[i] - rightSum[i]|
.
Where:
leftSum[i]
is the sum of elements to the left of the indexi
in the arraynums
. If there is no such element,leftSum[i] = 0
.rightSum[i]
is the sum of elements to the right of the indexi
in the arraynums
. If there is no such element,rightSum[i] = 0
.
Return the array answer
.
Example 1:
Input: nums = [10,4,8,3] Output: [15,1,11,22] Explanation: The array leftSum is [0,10,14,22] and the array rightSum is [15,11,3,0]. The array answer is [|0 - 15|,|10 - 11|,|14 - 3|,|22 - 0|] = [15,1,11,22].
Example 2:
Input: nums = [1] Output: [0] Explanation: The array leftSum is [0] and the array rightSum is [0]. The array answer is [|0 - 0|] = [0].
Constraints:
1 <= nums.length <= 1000
1 <= nums[i] <= 105