- Difficulty: Easy
- Tags: LeetCode, Easy, Hash Table, Linked List, Counting, leetcode-3063, O(n), O(1), Medium, 🔒
Problem
Given the head
of a linked list containing k
distinct elements, return the head to a linked list of length k
containing the frequency of each distinct element in the given linked list in any order.
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Example 1:
Input: head = [1,1,2,1,2,3]
Output: [3,2,1]
Explanation: There are 3
distinct elements in the list. The frequency of 1
is 3
, the frequency of 2
is 2
and the frequency of 3
is 1
. Hence, we return 3 -> 2 -> 1
.
Note that 1 -> 2 -> 3
, 1 -> 3 -> 2
, 2 -> 1 -> 3
, 2 -> 3 -> 1
, and 3 -> 1 -> 2
are also valid answers.
Example 2:
Input: head = [1,1,2,2,2]
Output: [2,3]
Explanation: There are 2
distinct elements in the list. The frequency of 1
is 2
and the frequency of 2
is 3
. Hence, we return 2 -> 3
.
Example 3:
Input: head = [6,5,4,3,2,1]
Output: [1,1,1,1,1,1]
Explanation: There are 6
distinct elements in the list. The frequency of each of them is 1
. Hence, we return 1 -> 1 -> 1 -> 1 -> 1 -> 1
.
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Constraints:
- The number of nodes in the list is in the range
[1, 105]
. 1 <= Node.val <= 105