- Difficulty: Easy
- Tags: LeetCode, Easy, Design, Hash Table, Data Stream, leetcode-359, O(1), amortized, O(k), 🔒, Deque
Problem
Design a logger system that receives a stream of messages along with their timestamps. Each unique message should only be printed at most every 10 seconds (i.e. a message printed at timestamp t
will prevent other identical messages from being printed until timestamp t + 10
).
All messages will come in chronological order. Several messages may arrive at the same timestamp.
Implement the Logger
class:
Logger()
Initializes thelogger
object.bool shouldPrintMessage(int timestamp, string message)
Returnstrue
if themessage
should be printed in the giventimestamp
, otherwise returnsfalse
.
Â
Example 1:
Input ["Logger", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage"] [[], [1, "foo"], [2, "bar"], [3, "foo"], [8, "bar"], [10, "foo"], [11, "foo"]] Output [null, true, true, false, false, false, true] Explanation Logger logger = new Logger(); logger.shouldPrintMessage(1, "foo"); // return true, next allowed timestamp for "foo" is 1 + 10 = 11 logger.shouldPrintMessage(2, "bar"); // return true, next allowed timestamp for "bar" is 2 + 10 = 12 logger.shouldPrintMessage(3, "foo"); // 3 < 11, return false logger.shouldPrintMessage(8, "bar"); // 8 < 12, return false logger.shouldPrintMessage(10, "foo"); // 10 < 11, return false logger.shouldPrintMessage(11, "foo"); // 11 >= 11, return true, next allowed timestamp for "foo" is 11 + 10 = 21
Â
Constraints:
0 <= timestamp <= 109
- Every
timestamp
will be passed in non-decreasing order (chronological order). 1 <= message.length <= 30
- At most
104
calls will be made toshouldPrintMessage
.