- Difficulty: Hard
- Tags: LeetCode, Hard, Greedy, Two Pointers, String, Dynamic Programming, Hash Function, Rolling Hash, leetcode-1147, O(n), O(1), Rabin-Karp Algorithm
Problem
You are given a string text
. You should split it to k substrings (subtext1, subtext2, ..., subtextk)
such that:
subtexti
is a non-empty string.- The concatenation of all the substrings is equal to
text
(i.e.,subtext1 + subtext2 + ... + subtextk == text
). subtexti == subtextk - i + 1
for all valid values ofi
(i.e.,1 <= i <= k
).
Return the largest possible value of k
.
Example 1:
Input: text = "ghiabcdefhelloadamhelloabcdefghi" Output: 7 Explanation: We can split the string on "(ghi)(abcdef)(hello)(adam)(hello)(abcdef)(ghi)".
Example 2:
Input: text = "merchant" Output: 1 Explanation: We can split the string on "(merchant)".
Example 3:
Input: text = "antaprezatepzapreanta" Output: 11 Explanation: We can split the string on "(a)(nt)(a)(pre)(za)(tep)(za)(pre)(a)(nt)(a)".
Constraints:
1 <= text.length <= 1000
text
consists only of lowercase English characters.