- Difficulty: Hard
- Tags: LeetCode, Hard, Trie, Array, String, leetcode-3093, O((n + q) * l), O(t)
Problem
You are given two arrays of strings wordsContainer
and wordsQuery
.
For each wordsQuery[i]
, you need to find a string from wordsContainer
that has the longest common suffix with wordsQuery[i]
. If there are two or more strings in wordsContainer
that share the longest common suffix, find the string that is the smallest in length. If there are two or more such strings that have the same smallest length, find the one that occurred earlier in wordsContainer
.
Return an array of integers ans
, where ans[i]
is the index of the string in wordsContainer
that has the longest common suffix with wordsQuery[i]
.
Example 1:
Input: wordsContainer = ["abcd","bcd","xbcd"], wordsQuery = ["cd","bcd","xyz"]
Output: [1,1,1]
Explanation:
Let's look at each wordsQuery[i]
separately:
- For
wordsQuery[0] = "cd"
, strings fromwordsContainer
that share the longest common suffix"cd"
are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3. - For
wordsQuery[1] = "bcd"
, strings fromwordsContainer
that share the longest common suffix"bcd"
are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3. - For
wordsQuery[2] = "xyz"
, there is no string fromwordsContainer
that shares a common suffix. Hence the longest common suffix is""
, that is shared with strings at index 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.
Example 2:
Input: wordsContainer = ["abcdefgh","poiuygh","ghghgh"], wordsQuery = ["gh","acbfgh","acbfegh"]
Output: [2,0,2]
Explanation:
Let's look at each wordsQuery[i]
separately:
- For
wordsQuery[0] = "gh"
, strings fromwordsContainer
that share the longest common suffix"gh"
are at indices 0, 1, and 2. Among these, the answer is the string at index 2 because it has the shortest length of 6. - For
wordsQuery[1] = "acbfgh"
, only the string at index 0 shares the longest common suffix"fgh"
. Hence it is the answer, even though the string at index 2 is shorter. - For
wordsQuery[2] = "acbfegh"
, strings fromwordsContainer
that share the longest common suffix"gh"
are at indices 0, 1, and 2. Among these, the answer is the string at index 2 because it has the shortest length of 6.
Constraints:
1 <= wordsContainer.length, wordsQuery.length <= 104
1 <= wordsContainer[i].length <= 5 * 103
1 <= wordsQuery[i].length <= 5 * 103
wordsContainer[i]
consists only of lowercase English letters.wordsQuery[i]
consists only of lowercase English letters.- Sum of
wordsContainer[i].length
is at most5 * 105
. - Sum of
wordsQuery[i].length
is at most5 * 105
.