- Difficulty: Medium
- Tags: LeetCode, Medium, Two Pointers, String, leetcode-2825, Greedy, O(n), O(1)
Problem
You are given two 0-indexed strings str1
and str2
.
In an operation, you select a set of indices in str1
, and for each index i
in the set, increment str1[i]
to the next character cyclically. That is 'a'
becomes 'b'
, 'b'
becomes 'c'
, and so on, and 'z'
becomes 'a'
.
Return true
if it is possible to make str2
a subsequence of str1
by performing the operation at most once, and false
otherwise.
Note: A subsequence of a string is a new string that is formed from the original string by deleting some (possibly none) of the characters without disturbing the relative positions of the remaining characters.
Example 1:
Input: str1 = "abc", str2 = "ad" Output: true Explanation: Select index 2 in str1. Increment str1[2] to become 'd'. Hence, str1 becomes "abd" and str2 is now a subsequence. Therefore, true is returned.
Example 2:
Input: str1 = "zc", str2 = "ad" Output: true Explanation: Select indices 0 and 1 in str1. Increment str1[0] to become 'a'. Increment str1[1] to become 'd'. Hence, str1 becomes "ad" and str2 is now a subsequence. Therefore, true is returned.
Example 3:
Input: str1 = "ab", str2 = "d" Output: false Explanation: In this example, it can be shown that it is impossible to make str2 a subsequence of str1 using the operation at most once. Therefore, false is returned.
Constraints:
1 <= str1.length <= 105
1 <= str2.length <= 105
str1
andstr2
consist of only lowercase English letters.