- Difficulty: Medium
- Tags: LeetCode, Medium, Bit Manipulation, Array, String, leetcode-318, O(n) ~ O(n^2), O(n), Counting Sort, Pruning
Problem
Given a string array words
, return the maximum value of length(word[i]) * length(word[j])
where the two words do not share common letters. If no such two words exist, return 0
.
Example 1:
Input: words = ["abcw","baz","foo","bar","xtfn","abcdef"] Output: 16 Explanation: The two words can be "abcw", "xtfn".
Example 2:
Input: words = ["a","ab","abc","d","cd","bcd","abcd"] Output: 4 Explanation: The two words can be "ab", "cd".
Example 3:
Input: words = ["a","aa","aaa","aaaa"] Output: 0 Explanation: No such pair of words.
Constraints:
2 <= words.length <= 1000
1 <= words[i].length <= 1000
words[i]
consists only of lowercase English letters.