- Difficulty: Medium
- Tags: LeetCode, Medium, Greedy, Binary Search, leetcode-1802, O(logm), O(1)
Problem
You are given three positive integers: n
, index
, and maxSum
. You want to construct an array nums
(0-indexed) that satisfies the following conditions:
nums.length == n
nums[i]
is a positive integer where0 <= i < n
.abs(nums[i] - nums[i+1]) <= 1
where0 <= i < n-1
.- The sum of all the elements of
nums
does not exceedmaxSum
. nums[index]
is maximized.
Return nums[index]
of the constructed array.
Note that abs(x)
equals x
if x >= 0
, and -x
otherwise.
Example 1:
Input: n = 4, index = 2, maxSum = 6 Output: 2 Explanation: nums = [1,2,2,1] is one array that satisfies all the conditions. There are no arrays that satisfy all the conditions and have nums[2] == 3, so 2 is the maximum nums[2].
Example 2:
Input: n = 6, index = 1, maxSum = 10 Output: 3
Constraints:
1 <= n <= maxSum <= 109
0 <= index < n