- Difficulty: Medium
- Tags: LeetCode, Medium, Linked List, Simulation, leetcode-2181, O(n), O(1), Two Pointers
Problem
You are given the head
of a linked list, which contains a series of integers separated by 0
's. The beginning and end of the linked list will have Node.val == 0
.
For every two consecutive 0
's, merge all the nodes lying in between them into a single node whose value is the sum of all the merged nodes. The modified list should not contain any 0
's.
Return the head
of the modified linked list.
Example 1:
Input: head = [0,3,1,0,4,5,2,0] Output: [4,11] Explanation: The above figure represents the given linked list. The modified list contains - The sum of the nodes marked in green: 3 + 1 = 4. - The sum of the nodes marked in red: 4 + 5 + 2 = 11.
Example 2:
Input: head = [0,1,0,3,0,2,2,0] Output: [1,3,4] Explanation: The above figure represents the given linked list. The modified list contains - The sum of the nodes marked in green: 1 = 1. - The sum of the nodes marked in red: 3 = 3. - The sum of the nodes marked in yellow: 2 + 2 = 4.
Constraints:
- The number of nodes in the list is in the range
[3, 2 * 105]
. 0 <= Node.val <= 1000
- There are no two consecutive nodes with
Node.val == 0
. - The beginning and end of the linked list have
Node.val == 0
.