- Difficulty: Medium
- Tags: LeetCode, Medium, Math, Binary Search, Number Theory, leetcode-2513, O(log(min(d1, d2))), O(1)
Problem
We have two arrays arr1
and arr2
which are initially empty. You need to add positive integers to them such that they satisfy all the following conditions:
arr1
containsuniqueCnt1
distinct positive integers, each of which is not divisible bydivisor1
.arr2
containsuniqueCnt2
distinct positive integers, each of which is not divisible bydivisor2
.- No integer is present in both
arr1
andarr2
.
Given divisor1
, divisor2
, uniqueCnt1
, and uniqueCnt2
, return the minimum possible maximum integer that can be present in either array.
Example 1:
Input: divisor1 = 2, divisor2 = 7, uniqueCnt1 = 1, uniqueCnt2 = 3 Output: 4 Explanation: We can distribute the first 4 natural numbers into arr1 and arr2. arr1 = [1] and arr2 = [2,3,4]. We can see that both arrays satisfy all the conditions. Since the maximum value is 4, we return it.
Example 2:
Input: divisor1 = 3, divisor2 = 5, uniqueCnt1 = 2, uniqueCnt2 = 1 Output: 3 Explanation: Here arr1 = [1,2], and arr2 = [3] satisfy all conditions. Since the maximum value is 3, we return it.
Example 3:
Input: divisor1 = 2, divisor2 = 4, uniqueCnt1 = 8, uniqueCnt2 = 2 Output: 15 Explanation: Here, the final possible arrays can be arr1 = [1,3,5,7,9,11,13,15], and arr2 = [2,6]. It can be shown that it is not possible to obtain a lower maximum satisfying all conditions.
Constraints:
2 <= divisor1, divisor2 <= 105
1 <= uniqueCnt1, uniqueCnt2 < 109
2 <= uniqueCnt1 + uniqueCnt2 <= 109