- Difficulty: Hard
- Tags: LeetCode, Hard, Greedy, Array, Binary Search, Prefix Sum, Sorting, leetcode-2448, O(nlogn), O(n), Math
Problem
You are given two 0-indexed arrays nums
and cost
consisting each of n
positive integers.
You can do the following operation any number of times:
- Increase or decrease any element of the array
nums
by1
.
The cost of doing one operation on the ith
element is cost[i]
.
Return the minimum total cost such that all the elements of the array nums
become equal.
Example 1:
Input: nums = [1,3,5,2], cost = [2,3,1,14]
Output: 8
Explanation: We can make all the elements equal to 2 in the following way:
- Increase the 0th element one time. The cost is 2.
- Decrease the 1st element one time. The cost is 3.
- Decrease the 2nd element three times. The cost is 1 + 1 + 1 = 3.
The total cost is 2 + 3 + 3 = 8.
It can be shown that we cannot make the array equal with a smaller cost.
Example 2:
Input: nums = [2,2,2,2,2], cost = [4,2,8,1,3] Output: 0 Explanation: All the elements are already equal, so no operations are needed.
Constraints:
n == nums.length == cost.length
1 <= n <= 105
1 <= nums[i], cost[i] <= 106
- Test cases are generated in a way that the output doesn't exceed 253-1