- Difficulty: Hard
- Tags: LeetCode, Hard, Array, Math, Number Theory, Sorting, Heap (Priority Queue), leetcode-2344, O(n + m + logr), O(1), GCD
Problem
You are given two positive integer arrays nums
and numsDivide
. You can delete any number of elements from nums
.
Return the minimum number of deletions such that the smallest element in nums
divides all the elements of numsDivide
. If this is not possible, return -1
.
Note that an integer x
divides y
if y % x == 0
.
Example 1:
Input: nums = [2,3,2,4,3], numsDivide = [9,6,9,3,15] Output: 2 Explanation: The smallest element in [2,3,2,4,3] is 2, which does not divide all the elements of numsDivide. We use 2 deletions to delete the elements in nums that are equal to 2 which makes nums = [3,4,3]. The smallest element in [3,4,3] is 3, which divides all the elements of numsDivide. It can be shown that 2 is the minimum number of deletions needed.
Example 2:
Input: nums = [4,3,6], numsDivide = [8,2,6,10] Output: -1 Explanation: We want the smallest element in nums to divide all the elements of numsDivide. There is no way to delete elements from nums to allow this.
Constraints:
1 <= nums.length, numsDivide.length <= 105
1 <= nums[i], numsDivide[i] <= 109