- Difficulty: Medium
- Tags: LeetCode, Medium, Greedy, Hash Table, String, Sorting, leetcode-1647, O(n), O(1)
Problem
A string s
is called good if there are no two different characters in s
that have the same frequency.
Given a string s
, return the minimum number of characters you need to delete to make s
good.
The frequency of a character in a string is the number of times it appears in the string. For example, in the string "aab"
, the frequency of 'a'
is 2
, while the frequency of 'b'
is 1
.
Example 1:
Input: s = "aab"
Output: 0
Explanation: s
is already good.
Example 2:
Input: s = "aaabbbcc" Output: 2 Explanation: You can delete two 'b's resulting in the good string "aaabcc". Another way it to delete one 'b' and one 'c' resulting in the good string "aaabbc".
Example 3:
Input: s = "ceabaacb" Output: 2 Explanation: You can delete both 'c's resulting in the good string "eabaab". Note that we only care about characters that are still in the string at the end (i.e. frequency of 0 is ignored).
Constraints:
1 <= s.length <= 105
s
contains only lowercase English letters.