- Difficulty: Medium
- Tags: LeetCode, Medium, Breadth-First Search, Array, Dynamic Programming, Matrix, leetcode-2850, Graph, O(n^3), O(n^2), Backtracking, Hungarian Weighted Bipartite Matching
Problem
You are given a 0-indexed 2D integer matrix grid
of size 3 * 3
, representing the number of stones in each cell. The grid contains exactly 9
stones, and there can be multiple stones in a single cell.
In one move, you can move a single stone from its current cell to any other cell if the two cells share a side.
Return the minimum number of moves required to place one stone in each cell.
Example 1:
Input: grid = [[1,1,0],[1,1,1],[1,2,1]] Output: 3 Explanation: One possible sequence of moves to place one stone in each cell is: 1- Move one stone from cell (2,1) to cell (2,2). 2- Move one stone from cell (2,2) to cell (1,2). 3- Move one stone from cell (1,2) to cell (0,2). In total, it takes 3 moves to place one stone in each cell of the grid. It can be shown that 3 is the minimum number of moves required to place one stone in each cell.
Example 2:
Input: grid = [[1,3,0],[1,0,0],[1,0,3]] Output: 4 Explanation: One possible sequence of moves to place one stone in each cell is: 1- Move one stone from cell (0,1) to cell (0,2). 2- Move one stone from cell (0,1) to cell (1,1). 3- Move one stone from cell (2,2) to cell (1,2). 4- Move one stone from cell (2,2) to cell (2,1). In total, it takes 4 moves to place one stone in each cell of the grid. It can be shown that 4 is the minimum number of moves required to place one stone in each cell.
Constraints:
grid.length == grid[i].length == 3
0 <= grid[i][j] <= 9
- Sum of
grid
is equal to9
.