- Difficulty: Hard
- Tags: LeetCode, Hard, Bit Manipulation, Breadth-First Search, Array, Hash Table, Matrix, leetcode-1284, O((m * n) * 2^(m * n))
Problem
Given a m x n
binary matrix mat
. In one step, you can choose one cell and flip it and all the four neighbors of it if they exist (Flip is changing 1
to 0
and 0
to 1
). A pair of cells are called neighbors if they share one edge.
Return the minimum number of steps required to convert mat
to a zero matrix or -1
if you cannot.
A binary matrix is a matrix with all cells equal to 0
or 1
only.
A zero matrix is a matrix with all cells equal to 0
.
Example 1:
Input: mat = [[0,0],[0,1]] Output: 3 Explanation: One possible solution is to flip (1, 0) then (0, 1) and finally (1, 1) as shown.
Example 2:
Input: mat = [[0]] Output: 0 Explanation: Given matrix is a zero matrix. We do not need to change it.
Example 3:
Input: mat = [[1,0,0],[1,0,0]] Output: -1 Explanation: Given matrix cannot be a zero matrix.
Constraints:
m == mat.length
n == mat[i].length
1 <= m, n <= 3
mat[i][j]
is either0
or1
.