- Difficulty: Hard
- Tags: LeetCode, Hard, Stack, Breadth-First Search, Union Find, Array, Dynamic Programming, Matrix, Monotonic Stack, Heap (Priority Queue), leetcode-2617, O(m * n), BFS, BST, Sorted List
Problem
You are given a 0-indexed m x n
integer matrix grid
. Your initial position is at the top-left cell (0, 0)
.
Starting from the cell (i, j)
, you can move to one of the following cells:
- Cells
(i, k)
withj < k <= grid[i][j] + j
(rightward movement), or - Cells
(k, j)
withi < k <= grid[i][j] + i
(downward movement).
Return the minimum number of cells you need to visit to reach the bottom-right cell (m - 1, n - 1)
. If there is no valid path, return -1
.
Example 1:
Input: grid = [[3,4,2,1],[4,2,3,1],[2,1,0,0],[2,4,0,0]] Output: 4 Explanation: The image above shows one of the paths that visits exactly 4 cells.
Example 2:
Input: grid = [[3,4,2,1],[4,2,1,1],[2,1,1,0],[3,4,1,0]] Output: 3 Explanation: The image above shows one of the paths that visits exactly 3 cells.
Example 3:
Input: grid = [[2,1,0],[1,0,0]] Output: -1 Explanation: It can be proven that no path exists.
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 105
1 <= m * n <= 105
0 <= grid[i][j] < m * n
grid[m - 1][n - 1] == 0