- Difficulty: Medium
- Tags: LeetCode, Medium, Greedy, Bit Manipulation, Dynamic Programming, leetcode-2571, O(logn), O(1), Trick
Problem
You are given a positive integer n
, you can do the following operation any number of times:
- Add or subtract a power of
2
fromn
.
Return the minimum number of operations to make n
equal to 0
.
A number x
is power of 2
if x == 2i
where i >= 0
.
Example 1:
Input: n = 39 Output: 3 Explanation: We can do the following operations: - Add 20 = 1 to n, so now n = 40. - Subtract 23 = 8 from n, so now n = 32. - Subtract 25 = 32 from n, so now n = 0. It can be shown that 3 is the minimum number of operations we need to make n equal to 0.
Example 2:
Input: n = 54 Output: 3 Explanation: We can do the following operations: - Add 21 = 2 to n, so now n = 56. - Add 23 = 8 to n, so now n = 64. - Subtract 26 = 64 from n, so now n = 0. So the minimum number of operations is 3.
Constraints:
1 <= n <= 105