- Difficulty: Medium
- Tags: LeetCode, Medium, leetcode-3144, Dynamic Programming, O(n * (n + 26)), O(n + 26), DP, Freq Table, Hash Table, String, Counting
Problem
Given a string s
, you need to partition it into one or more balanced substrings. For example, if s == "ababcc"
then ("abab", "c", "c")
, ("ab", "abc", "c")
, and ("ababcc")
are all valid partitions, but ("a", "bab", "cc")
, ("aba", "bc", "c")
, and ("ab", "abcc")
are not. The unbalanced substrings are bolded.
Return the minimum number of substrings that you can partition s
into.
Note: A balanced string is a string where each character in the string occurs the same number of times.
Example 1:
Input: s = "fabccddg"
Output: 3
Explanation:
We can partition the string s
into 3 substrings in one of the following ways: ("fab, "ccdd", "g")
, or ("fabc", "cd", "dg")
.
Example 2:
Input: s = "abababaccddb"
Output: 2
Explanation:
We can partition the string s
into 2 substrings like so: ("abab", "abaccddb")
.
Constraints:
1 <= s.length <= 1000
s
consists only of English lowercase letters.