- Difficulty: Easy
- Tags: LeetCode, Easy, Array, Hash Table, Counting, leetcode-2190, O(n), Freq Table
Problem
You are given a 0-indexed integer array nums
. You are also given an integer key
, which is present in nums
.
For every unique integer target
in nums
, count the number of times target
immediately follows an occurrence of key
in nums
. In other words, count the number of indices i
such that:
0 <= i <= nums.length - 2
,nums[i] == key
and,nums[i + 1] == target
.
Return the target
with the maximum count. The test cases will be generated such that the target
with maximum count is unique.
Example 1:
Input: nums = [1,100,200,1,100], key = 1 Output: 100 Explanation: For target = 100, there are 2 occurrences at indices 1 and 4 which follow an occurrence of key. No other integers follow an occurrence of key, so we return 100.
Example 2:
Input: nums = [2,2,2,2,3], key = 2 Output: 2 Explanation: For target = 2, there are 3 occurrences at indices 1, 2, and 3 which follow an occurrence of key. For target = 3, there is only one occurrence at index 4 which follows an occurrence of key. target = 2 has the maximum number of occurrences following an occurrence of key, so we return 2.
Constraints:
2 <= nums.length <= 1000
1 <= nums[i] <= 1000
- The test cases will be generated such that the answer is unique.