- Difficulty: Hard
- Tags: LeetCode, Hard, Bit Manipulation, Trie, Array, Hash Table, String, leetcode-1178, O(n * l + m * L), O(L!)
Problem
With respect to a given
puzzle
string, a word
is valid if both the following conditions are satisfied:
word
contains the first letter ofpuzzle
.- For each letter in
word
, that letter is inpuzzle
.- For example, if the puzzle is
"abcdefg"
, then valid words are"faced"
,"cabbage"
, and"baggage"
, while - invalid words are
"beefed"
(does not include'a'
) and"based"
(includes's'
which is not in the puzzle).
- For example, if the puzzle is
answer
, where answer[i]
is the number of words in the given word list words
that is valid with respect to the puzzle puzzles[i]
.
Example 1:
Input: words = ["aaaa","asas","able","ability","actt","actor","access"], puzzles = ["aboveyz","abrodyz","abslute","absoryz","actresz","gaswxyz"] Output: [1,1,3,2,4,0] Explanation: 1 valid word for "aboveyz" : "aaaa" 1 valid word for "abrodyz" : "aaaa" 3 valid words for "abslute" : "aaaa", "asas", "able" 2 valid words for "absoryz" : "aaaa", "asas" 4 valid words for "actresz" : "aaaa", "asas", "actt", "access" There are no valid words for "gaswxyz" cause none of the words in the list contains letter 'g'.
Example 2:
Input: words = ["apple","pleas","please"], puzzles = ["aelwxyz","aelpxyz","aelpsxy","saelpxy","xaelpsy"] Output: [0,1,3,2,0]
Constraints:
1 <= words.length <= 105
4 <= words[i].length <= 50
1 <= puzzles.length <= 104
puzzles[i].length == 7
words[i]
andpuzzles[i]
consist of lowercase English letters.- Each
puzzles[i]
does not contain repeated characters.