- Difficulty: Medium
- Tags: LeetCode, Medium, Array, Hash Table, Counting, leetcode-1010, O(n), O(1), Easy
Problem
You are given a list of songs where the ith
song has a duration of time[i]
seconds.
Return the number of pairs of songs for which their total duration in seconds is divisible by 60
. Formally, we want the number of indices i
, j
such that i < j
with (time[i] + time[j]) % 60 == 0
.
Example 1:
Input: time = [30,20,150,100,40] Output: 3 Explanation: Three pairs have a total duration divisible by 60: (time[0] = 30, time[2] = 150): total duration 180 (time[1] = 20, time[3] = 100): total duration 120 (time[1] = 20, time[4] = 40): total duration 60
Example 2:
Input: time = [60,60,60] Output: 3 Explanation: All three pairs have a total duration of 120, which is divisible by 60.
Constraints:
1 <= time.length <= 6 * 104
1 <= time[i] <= 500