- Difficulty: Medium
- Tags: LeetCode, Medium, Binary Indexed Tree, Segment Tree, Array, Sorting, leetcode-406, Sort, O(n * sqrt(n)), O(n), Tricky
Problem
You are given an array of people, people
, which are the attributes of some people in a queue (not necessarily in order). Each people[i] = [hi, ki]
represents the ith
person of height hi
with exactly ki
other people in front who have a height greater than or equal to hi
.
Reconstruct and return the queue that is represented by the input array people
. The returned queue should be formatted as an array queue
, where queue[j] = [hj, kj]
is the attributes of the jth
person in the queue (queue[0]
is the person at the front of the queue).
Example 1:
Input: people = [[7,0],[4,4],[7,1],[5,0],[6,1],[5,2]] Output: [[5,0],[7,0],[5,2],[6,1],[4,4],[7,1]] Explanation: Person 0 has height 5 with no other people taller or the same height in front. Person 1 has height 7 with no other people taller or the same height in front. Person 2 has height 5 with two persons taller or the same height in front, which is person 0 and 1. Person 3 has height 6 with one person taller or the same height in front, which is person 1. Person 4 has height 4 with four people taller or the same height in front, which are people 0, 1, 2, and 3. Person 5 has height 7 with one person taller or the same height in front, which is person 1. Hence [[5,0],[7,0],[5,2],[6,1],[4,4],[7,1]] is the reconstructed queue.
Example 2:
Input: people = [[6,0],[5,0],[4,0],[3,2],[2,2],[1,4]] Output: [[4,0],[5,0],[2,2],[3,2],[1,4],[6,0]]
Constraints:
1 <= people.length <= 2000
0 <= hi <= 106
0 <= ki < people.length
- It is guaranteed that the queue can be reconstructed.