- Difficulty: Hard
- Tags: LeetCode, Hard, Greedy, Array, Hash Table, leetcode-2561, O(n) on average, O(n), Freq Table, Quick Select
Problem
You have two fruit baskets containing n
fruits each. You are given two 0-indexed integer arrays basket1
and basket2
representing the cost of fruit in each basket. You want to make both baskets equal. To do so, you can use the following operation as many times as you want:
- Chose two indices
i
andj
, and swap theith
fruit ofbasket1
with thejth
fruit ofbasket2
. - The cost of the swap is
min(basket1[i],basket2[j])
.
Two baskets are considered equal if sorting them according to the fruit cost makes them exactly the same baskets.
Return the minimum cost to make both the baskets equal or -1
if impossible.
Example 1:
Input: basket1 = [4,2,2,2], basket2 = [1,4,1,2] Output: 1 Explanation: Swap index 1 of basket1 with index 0 of basket2, which has cost 1. Now basket1 = [4,1,2,2] and basket2 = [2,4,1,2]. Rearranging both the arrays makes them equal.
Example 2:
Input: basket1 = [2,3,4,1], basket2 = [3,2,5,1] Output: -1 Explanation: It can be shown that it is impossible to make both the baskets equal.
Constraints:
basket1.length == basket2.length
1 <= basket1.length <= 105
1 <= basket1[i],basket2[i] <= 109