- Difficulty: Medium
- Tags: LeetCode, Medium, Tree, Depth-First Search, Binary Search Tree, Binary Tree, leetcode-99, O(n), O(1), Hard, Morris Traversal
Problem
You are given the root
of a binary search tree (BST), where the values of exactly two nodes of the tree were swapped by mistake. Recover the tree without changing its structure.
Example 1:
Input: root = [1,3,null,null,2] Output: [3,1,null,null,2] Explanation: 3 cannot be a left child of 1 because 3 > 1. Swapping 1 and 3 makes the BST valid.
Example 2:
Input: root = [3,1,4,null,null,2] Output: [2,1,4,null,null,3] Explanation: 2 cannot be in the right subtree of 3 because 2 < 3. Swapping 2 and 3 makes the BST valid.
Constraints:
- The number of nodes in the tree is in the range
[2, 1000]
. -231 <= Node.val <= 231 - 1
Follow up: A solution using
O(n)
space is pretty straight-forward. Could you devise a constant O(1)
space solution?