- Difficulty: Hard
- Tags: LeetCode, Hard, Depth-First Search, Breadth-First Search, Array, Binary Search, Matrix, leetcode-302, O(nlogn), O(1), 🔒
Problem
You are given an m x n binary matrix image where 0 represents a white pixel and 1 represents a black pixel.
The black pixels are connected (i.e., there is only one black region). Pixels are connected horizontally and vertically.
Given two integers x and y that represents the location of one of the black pixels, return the area of the smallest (axis-aligned) rectangle that encloses all black pixels.
You must write an algorithm with less than O(mn) runtime complexity
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Example 1:
Input: image = [["0","0","1","0"],["0","1","1","0"],["0","1","0","0"]], x = 0, y = 2 Output: 6
Example 2:
Input: image = [["1"]], x = 0, y = 0 Output: 1
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Constraints:
m == image.lengthn == image[i].length1 <= m, n <= 100image[i][j]is either'0'or'1'.0 <= x < m0 <= y < nimage[x][y] == '1'.- The black pixels in the
imageonly form one component.