- Difficulty: Medium
- Tags: LeetCode, Medium, String, Sorting, leetcode-2785, Sort, O(n), O(1), Counting Sort
Problem
Given a 0-indexed string s
, permute s
to get a new string t
such that:
- All consonants remain in their original places. More formally, if there is an index
i
with0 <= i < s.length
such thats[i]
is a consonant, thent[i] = s[i]
. - The vowels must be sorted in the nondecreasing order of their ASCII values. More formally, for pairs of indices
i
,j
with0 <= i < j < s.length
such thats[i]
ands[j]
are vowels, thent[i]
must not have a higher ASCII value thant[j]
.
Return the resulting string.
The vowels are 'a'
, 'e'
, 'i'
, 'o'
, and 'u'
, and they can appear in lowercase or uppercase. Consonants comprise all letters that are not vowels.
Example 1:
Input: s = "lEetcOde" Output: "lEOtcede" Explanation: 'E', 'O', and 'e' are the vowels in s; 'l', 't', 'c', and 'd' are all consonants. The vowels are sorted according to their ASCII values, and the consonants remain in the same places.
Example 2:
Input: s = "lYmpH" Output: "lYmpH" Explanation: There are no vowels in s (all characters in s are consonants), so we return "lYmpH".
Constraints:
1 <= s.length <= 105
s
consists only of letters of the English alphabet in uppercase and lowercase.