Problem
Given a positive integer num
, split it into two non-negative integers num1
and num2
such that:
- The concatenation of
num1
andnum2
is a permutation ofnum
.- In other words, the sum of the number of occurrences of each digit in
num1
andnum2
is equal to the number of occurrences of that digit innum
.
- In other words, the sum of the number of occurrences of each digit in
num1
andnum2
can contain leading zeros.
Return the minimum possible sum of num1
and num2
.
Notes:
- It is guaranteed that
num
does not contain any leading zeros. - The order of occurrence of the digits in
num1
andnum2
may differ from the order of occurrence ofnum
.
Example 1:
Input: num = 4325 Output: 59 Explanation: We can split 4325 so thatnum1
is 24 andnum2
is 35, giving a sum of 59. We can prove that 59 is indeed the minimal possible sum.
Example 2:
Input: num = 687 Output: 75 Explanation: We can split 687 so thatnum1
is 68 andnum2
is 7, which would give an optimal sum of 75.
Constraints:
10 <= num <= 109