- Difficulty: Easy
- Tags: LeetCode, Easy, Array, Binary Search, Matrix, Sorting, Heap (Priority Queue), leetcode-1337, O(m * n), O(k), OrderedDict, Quick Select
Problem
You are given an m x n
binary matrix mat
of 1
's (representing soldiers) and 0
's (representing civilians). The soldiers are positioned in front of the civilians. That is, all the 1
's will appear to the left of all the 0
's in each row.
A row i
is weaker than a row j
if one of the following is true:
- The number of soldiers in row
i
is less than the number of soldiers in rowj
. - Both rows have the same number of soldiers and
i < j
.
Return the indices of the k
weakest rows in the matrix ordered from weakest to strongest.
Example 1:
Input: mat = [[1,1,0,0,0], [1,1,1,1,0], [1,0,0,0,0], [1,1,0,0,0], [1,1,1,1,1]], k = 3 Output: [2,0,3] Explanation: The number of soldiers in each row is: - Row 0: 2 - Row 1: 4 - Row 2: 1 - Row 3: 2 - Row 4: 5 The rows ordered from weakest to strongest are [2,0,3,1,4].
Example 2:
Input: mat = [[1,0,0,0], [1,1,1,1], [1,0,0,0], [1,0,0,0]], k = 2 Output: [0,2] Explanation: The number of soldiers in each row is: - Row 0: 1 - Row 1: 4 - Row 2: 1 - Row 3: 1 The rows ordered from weakest to strongest are [0,2,3,1].
Constraints:
m == mat.length
n == mat[i].length
2 <= n, m <= 100
1 <= k <= m
matrix[i][j]
is either 0 or 1.