- Difficulty: Medium
- Tags: LeetCode, Medium, Design, Hash Table, String, Binary Search, leetcode-981, O(n)
Problem
Design a time-based key-value data structure that can store multiple values for the same key at different time stamps and retrieve the key's value at a certain timestamp.
Implement the TimeMap
class:
TimeMap()
Initializes the object of the data structure.void set(String key, String value, int timestamp)
Stores the keykey
with the valuevalue
at the given timetimestamp
.String get(String key, int timestamp)
Returns a value such thatset
was called previously, withtimestamp_prev <= timestamp
. If there are multiple such values, it returns the value associated with the largesttimestamp_prev
. If there are no values, it returns""
.
Example 1:
Input ["TimeMap", "set", "get", "get", "set", "get", "get"] [[], ["foo", "bar", 1], ["foo", 1], ["foo", 3], ["foo", "bar2", 4], ["foo", 4], ["foo", 5]] Output [null, null, "bar", "bar", null, "bar2", "bar2"] Explanation TimeMap timeMap = new TimeMap(); timeMap.set("foo", "bar", 1); // store the key "foo" and value "bar" along with timestamp = 1. timeMap.get("foo", 1); // return "bar" timeMap.get("foo", 3); // return "bar", since there is no value corresponding to foo at timestamp 3 and timestamp 2, then the only value is at timestamp 1 is "bar". timeMap.set("foo", "bar2", 4); // store the key "foo" and value "bar2" along with timestamp = 4. timeMap.get("foo", 4); // return "bar2" timeMap.get("foo", 5); // return "bar2"
Constraints:
1 <= key.length, value.length <= 100
key
andvalue
consist of lowercase English letters and digits.1 <= timestamp <= 107
- All the timestamps
timestamp
ofset
are strictly increasing. - At most
2 * 105
calls will be made toset
andget
.