- Difficulty: Hard
- Tags: LeetCode, Hard, Array, Math, String, Backtracking, leetcode-1307, O(10! * n * l), O(n * l)
Problem
Given an equation, represented by words
on the left side and the result
on the right side.
You need to check if the equation is solvable under the following rules:
- Each character is decoded as one digit (0 - 9).
- No two characters can map to the same digit.
- Each
words[i]
andresult
are decoded as one number without leading zeros. - Sum of numbers on the left side (
words
) will equal to the number on the right side (result
).
Return true
if the equation is solvable, otherwise return false
.
Example 1:
Input: words = ["SEND","MORE"], result = "MONEY" Output: true Explanation: Map 'S'-> 9, 'E'->5, 'N'->6, 'D'->7, 'M'->1, 'O'->0, 'R'->8, 'Y'->'2' Such that: "SEND" + "MORE" = "MONEY" , 9567 + 1085 = 10652
Example 2:
Input: words = ["SIX","SEVEN","SEVEN"], result = "TWENTY" Output: true Explanation: Map 'S'-> 6, 'I'->5, 'X'->0, 'E'->8, 'V'->7, 'N'->2, 'T'->1, 'W'->'3', 'Y'->4 Such that: "SIX" + "SEVEN" + "SEVEN" = "TWENTY" , 650 + 68782 + 68782 = 138214
Example 3:
Input: words = ["LEET","CODE"], result = "POINT" Output: false Explanation: There is no possible mapping to satisfy the equation, so we return false. Note that two different characters cannot map to the same digit.
Constraints:
2 <= words.length <= 5
1 <= words[i].length, result.length <= 7
words[i], result
contain only uppercase English letters.- The number of different characters used in the expression is at most
10
.