- Difficulty: Medium
- Tags: LeetCode, Medium, Hash Table, String, Backtracking, leetcode-291, O(n * C(n - 1, c - 1)), O(n + c), Hard, 🔒
Problem
Given a pattern
and a string s
, return true
if s
matches the pattern
.
A string s
matches a pattern
if there is some bijective mapping of single characters to non-empty strings such that if each character in pattern
is replaced by the string it maps to, then the resulting string is s
. A bijective mapping means that no two characters map to the same string, and no character maps to two different strings.
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Example 1:
Input: pattern = "abab", s = "redblueredblue" Output: true Explanation: One possible mapping is as follows: 'a' -> "red" 'b' -> "blue"
Example 2:
Input: pattern = "aaaa", s = "asdasdasdasd" Output: true Explanation: One possible mapping is as follows: 'a' -> "asd"
Example 3:
Input: pattern = "aabb", s = "xyzabcxzyabc" Output: false
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Constraints:
1 <= pattern.length, s.length <= 20
pattern
ands
consist of only lowercase English letters.